You are given a 0-indexed array of integers nums of length n. You are initially positioned at nums[0].
Each element nums[i] represents the maximum length of a forward jump from index i. In other words, if you are at nums[i], you can jump to any nums[i + j] where 0 <= j <= nums[i] and i + j < n.
Return the minimum number of jumps to reach nums[n - 1]. The test cases are generated such that you can reach nums[n - 1].
nums = [2,3,1,1,4]2nums = [2,3,0,1,4]2nums = [1]01 <= nums.length <= 10^40 <= nums[i] <= 1000It's guaranteed that you can reach nums[n - 1]Expected time complexity: O(n)Run your code to see results
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